2x^2+2x-24=(2x-6)

Solution for 2x^2+2x-24=(2x-6) equation:

2x^2+2x-24=(2x-6)

We move all terms to the left:

2x^2+2x-24-((2x-6))=0


We calculate terms in parentheses: -((2x-6)), so:

(2x-6)

We get rid of parentheses

2x-6

Back to the equation:

-(2x-6)


We get rid of parentheses

2x^2+2x-2x+6-24=0

We add all the numbers together, and all the variables

2x^2-18=0

a = 2; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·2·(-18)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*2}=\frac{-12}{4}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*2}=\frac{12}{4}
=3
$